ThermodynamicsHard
Question
5.6 liter of helium gas at STP is adiabatically compressed to 0.7 lit. Taking the initial temperaure to be T1, the work done in the process is
Options
A.
B.
C.
D.
Solution
TVγ-1 = C
T2 (0.7)2/3 ⇒ T2 = T1(8)2/3 = 4T1
∴ᐃw (work done on the system)
T2 (0.7)2/3 ⇒ T2 = T1(8)2/3 = 4T1
∴ᐃw (work done on the system)
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