ThermodynamicsHard

Question

Two moles of helium gas are taken over the cycle ABCDA, as shown in the P - T diagram.
       
Assuming the gas to be ideal the work done on the gas in taking it from A to B is

Options

A.200 R
B.300 R
C.400 R
D.500 R

Solution

       
WAB = ᐃQ - ᐃU = nCpdT - nCvdT (at constant pressure)
= n(Cp - Cv)dt
= nRdT = 2 × R × (500 - 300) = 400 R

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