Chemical BondingEasy
Question
The graph between log(x/m) and log P is a straight line at angle 45o with intercept OA as shown. Hence (x/m) at a pressure of 2 atm is
Options
A.2
B.4
C.8
D.1
Solution
log 
= log K + 1/x log P
log K = log 2
1/n = 1
x/m = K (P)1/n = 4
= log K + 1/x log Plog K = log 2
1/n = 1
x/m = K (P)1/n = 4
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