Chemical BondingHard

Question

Cu+ + e- → Cu    Eo = a1 volt
Cu+2 + 2e- → Cu    Eo = a2 volt
then for Cu2+ + e- → Cu+, Eo will be :-

Options

A.a1 - 2a2
B.a2 - a1
C.a1 - a2
D.2a2 - a1

Solution

(1) Cu+ + e- → Cu; ᐃGo1
(2) Cu2+ + 2e- → Cu; ᐃGo2
Now on eqn. (2) - eqn (1)
Cu2+ + e- → Cu+; ᐃGo3 = ᐃGo2 - ᐃGo1
or    - n3FEo3 = - n2FEo2 - (-n1FEo1)
-1 × Eo3 = - 2 × Eo2 + 1 × Eo1
Eo3 = 2a2 -a1

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