SolutionHard
Question
Aqueous solution of barium phosphate which is 100% ionised has ᐃTf / Kf as 0.05. Hence, given solution is
Options
A.0.01 molal
B.0.02 molal
C.0.04 molal
D.0.05 molal
Solution
Ba3(PO4)2 ⇋ 3 Ba2+ + 2 PO43-
value of i = 5 (100% ionised)
so ᐃTf = i kf m
so m =
= 0.01
value of i = 5 (100% ionised)
so ᐃTf = i kf m
so m =
= 0.01Create a free account to view solution
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