SolutionHard
Question
How many grams of sucrose (molecular weight = 342) should be dissolved in 100 g water in order to produce a solution with a 104.76°C difference between the freezing point and the boiling point temperature? (Kf = 1.86, Kb = 0.52)
Options
A.34.2 g
B.68.4 g
C.684 g
D.313.06 g
Solution
$\Delta T_{f} + \Delta T_{b} = \left( K_{f} + K_{b} \right).m$
Or, $4.76 = (1.86 + 0.52) \times \frac{w/342}{100/1000} \Rightarrow w = 68.4\text{ gm}$
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