SolutionHard
Question
A Solution of sucrose (molar mass = 342 gm-mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The Freezing point of the solution obtained will be
(Kf for water = 1.86 K kg mol-1)
(Kf for water = 1.86 K kg mol-1)
Options
A.- 0.372oC
B.- 0.520oC
C.+ 0.372oC
D.- 0.570oC
Solution
Depression in freezing point
ᐃ Tf = kf × m
where, m = molality =
ᐃTf = 1.86 ×
= 0.372oC
ᐃTf = To - Ts
= 0 - 0.372oC
= - 0.372oC
ᐃ Tf = kf × m
where, m = molality =
ᐃTf = 1.86 ×
= 0.372oC
ᐃTf = To - Ts
= 0 - 0.372oC
= - 0.372oC
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