SolutionHard
Question
The vapour pressure of pure liquid solvent A is 0.80 atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the component B in the solution is :
Options
A.0.50
B.0.25
C.0.75
D.0.40
Solution
Acc. to R.L. V.P. ⇒ 
= XB
XB =
= 0.25.
= XBXB =
= 0.25.Create a free account to view solution
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