SolutionHard
Question
Density of 1M solution of a non-electrolyte C6H12O6 is 1.18 g/mL. If Kf (H2O) is 1.86o mol-1 kg, solution freezes at :
Options
A.- 1.58oC
B.- 1.86oC
C.- 3.16oC
D.1.86oC
Solution
1M C6H12O6 (molar mass = 180 g mol-1)
1000 mL solution has = 180 g solute
1180 g solution has = 180 g solute
1000 g solvent has = 180 g solute
Thus, molality = 1 molal
∴ ᐃTf = Kf molality
= 1.86 × 1 = 1.86o
∴ F.P. = - 1.86oC
1000 mL solution has = 180 g solute
1180 g solution has = 180 g solute
1000 g solvent has = 180 g solute
Thus, molality = 1 molal
∴ ᐃTf = Kf molality
= 1.86 × 1 = 1.86o
∴ F.P. = - 1.86oC
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