SolutionHard
Question
Liquids A and B form an ideal solution. The plot of $\frac{1}{X_{A}}$ (Y-axis) versus$\frac{1}{Y_{A}}$ (X-axis) (where XA and YA are the mole fractions of A in liquid and vapour phases at equilibrium, respectively) is linear whose slope and intercept, respectively, are given as
Options
A.$\frac{P_{A}^{o}}{P_{B}^{o}},\frac{\left( P_{A}^{o} - P_{B}^{o} \right)}{P_{B}^{o}}$
B.$\frac{P_{A}^{o}}{P_{B}^{o}},\frac{\left( P_{B}^{o} - P_{A}^{o} \right)}{P_{B}^{o}}$
C.$\frac{P_{B}^{o}}{P_{A}^{o}},\frac{\left( P_{A}^{o} - P_{B}^{o} \right)}{P_{B}^{o}}$
D.$\frac{P_{B}^{o}}{P_{A}^{o}},\frac{\left( P_{B}^{o} - P_{A}^{o} \right)}{P_{B}^{o}}$
Solution
$Y_{A} = \frac{P_{A}}{P_{\text{total}}} = \frac{X_{A}.P_{A}^{o}}{P_{\text{total}}}$
$\frac{1}{X_{A}} = \frac{1}{Y_{A}}.P_{A}^{o}.\left( \frac{Y_{A}}{P_{A}^{o}} + \frac{\left( 1 - Y_{A} \right)}{P_{B}^{o}} \right) = \frac{1}{Y_{A}}.\frac{P_{A}^{o}}{P_{B}^{o}} + \frac{P_{B}^{o} - P_{A}^{o}}{P_{B}^{o}}$
Create a free account to view solution
View Solution FreeMore Solution Questions
Consider two liquids A & B having pure vapour pressures PAo & PBo forming an ideal solution. The plot of v/s (where XA a...The freezing point depression of 0.001 m Kx[Fe(CN)6] is 7.10 × 10-3 K. Determine the value of x ? (Given Kƒ = ...pressure cooker reduces cooking time for food because...The pH vlues of aqueous solutions of which of the following compounds does not change on dilution ?...At 323 K, the vapour pressure in millimeters of mercury of a methanol-ethanol solution is represented by the equation p ...