Coordination CompoundHard
Question
The total number of possible isomers of the compound [CuII(NH3)4] [PtIICl4] are:
Options
A.3
B.5
C.4
D.6
Solution
(C) There are four possible coordination isomers as given below :
(i)[CuII(NH3)4] [PtII Cl4]
(ii)[PtII (NH3)4] [CuIICl4]
(iii)[CuII (NH3)3 Cl] [PtII (NH3)Cl3]
(vi) [PtII (NH3)3 Cl] [CuII (NH3)Cl3]
(i)[CuII(NH3)4] [PtII Cl4]
(ii)[PtII (NH3)4] [CuIICl4]
(iii)[CuII (NH3)3 Cl] [PtII (NH3)Cl3]
(vi) [PtII (NH3)3 Cl] [CuII (NH3)Cl3]
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