Coordination CompoundHardBloom L3

Question

The tetrahedral [CoI4]2– and square planar [PdBr4]2– complex ions are respectively

Options

A.low spin, high spin
B.high spin, low spin
C.both low spin
D.both high spin

Solution

Sol. [CoI4]–2 = Co+2 [PdBr4]–2

Co+2 = 3d7 Pd+2 = 4d8

CO is S.F.L. dsp2 ⇒ no u.p.e. ⇒ low spin complex

sp3 ⇒ 3 u.p.e.

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