Coordination CompoundHardBloom L3

Question

The tetrahedral [CoI4]2– and square planar [PdBr4]2– complex ions are respectively

Options

A.low spin, high spin
B.high spin, low spin
C.both low spin
D.both high spin

Solution

Sol. [CoI4]–2 = Co+2 [PdBr4]–2

Co+2 = 3d7 Pd+2 = 4d8

CO is S.F.L. dsp2 ⇒ no u.p.e. ⇒ low spin complex

sp3 ⇒ 3 u.p.e.

Create a free account to view solution

View Solution Free
Topic: Coordination Compound·Practice all Coordination Compound questions

More Coordination Compound Questions

Consider the complex ion [Cr (NH3)2(C2O4)2] ¯. What is the (i) oxidation number of the metal atom. (ii) coordination num...The purple colour of KMnO4 is due to the transition...Which one of the following statement is false for nickel-dimethylglyoximate complex ?...The oxidation state of Mo in its oxido-complex species [Mo2O4(C2H4)2(H2O)2]2- is...Which of the following is not onsidered as an organometallic compound ?...