Atomic StructureHard
Question
The electron in the hydrogen atom jumps from excited state (n = 3) to its ground state (n = 1) and the photons thus emitted irradiate a phonsenstive material. If the work function of material is 5.1 eV, the stopping potential is estimated to be (the energy of the electron in nth state En = - 
eV)
eV)Options
A.5.1 V
B.12.1 V
C.17.2 V
D.7 V
Solution
Energy released when electrons in the atom jumps from excited state (n = 3) to ground state (n = 1) is
E = h
= E3 - E1 = 
=
+ 13.6 = 12.1eV
Therefore, stopping potential
eV0 = hv - φ0
= 12.1 - 5.1 [∵ work function φ0 = 5.1]
V0 = 7V.
E = h
= E3 - E1 = =
+ 13.6 = 12.1eVTherefore, stopping potential
eV0 = hv - φ0
= 12.1 - 5.1 [∵ work function φ0 = 5.1]
V0 = 7V.
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