Atomic StructureHard

Question

Nuclear reactions are given as -
(i) ⎕ (n, p)15p32
(ii) ⎕ (p, α)8O16
(iii) 7N14 (⎕, p) 6C14
missing particle or nuclide in box ⎕ in these reactions are respectively :-

Options

A.S32, F19, 0n1
B.F19, S32, 0n1
C.Be9, F19, 0n1
D.None of these

Solution

(1)aXb(n, P)15P32
aXb + 0n11P1 + 15P32
b + 1 = 33 ⇒ b = 32
a + 0 = 16 ⇒ a = 16
Similarly for (2) and (3)

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