NEETIonic EquilibriumHard
Question
At what molar concentration of HCl will its aqueous solution have an [H+] to which equal contributions come from HCl and H2O.
Options
A.
× 10-7 M
× 10-7 MB.
× 10-8 M
× 10-8 MC.
× 10-9 M
× 10-9 MD.
× 10-8 M
× 10-8 MSolution
HCl → H+ + Cl-
(x + x) (x)
H2O ⇋ H+ + OH-
(x + x) (x)
Ionic product = Kw = (2x) (x) = 10-14
⇒ 2x2 = 10-14 ⇒ x =
× 10-8
(x + x) (x)
H2O ⇋ H+ + OH-
(x + x) (x)
Ionic product = Kw = (2x) (x) = 10-14
⇒ 2x2 = 10-14 ⇒ x =
× 10-8 Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
A solution has initially 0.1 M-HCOOH and 0.2 M-HCN. The value of Ka for HCOOH = 2.56 × 10−5, Ka of HCN = 9.6 × 10−10. Th...Saccharin (Ka = 2 × 10–12) is a weak acid represented by the formula HSac. A 4 × 10–4 mole amount of saccharin is dissol...The pH of an acidic buffer mixture is:...Given Ag(NH3)2+$\rightleftharpoons$ Ag+ + 2NH3, Kc = 7.2 × 10–8 and Ksp of AgCl = 1.8 × 10–10 at 298 K. If ammonia is a...20 cm3 of x M solution of HCl is exactly neutralised by 40 cm3 of 0.05 M NaOH solution, the pH of HCl solution is...