NEETIonic EquilibriumHard
Question
At what molar concentration of HCl will its aqueous solution have an [H+] to which equal contributions come from HCl and H2O.
Options
A.
× 10-7 M
× 10-7 MB.
× 10-8 M
× 10-8 MC.
× 10-9 M
× 10-9 MD.
× 10-8 M
× 10-8 MSolution
HCl → H+ + Cl-
(x + x) (x)
H2O ⇋ H+ + OH-
(x + x) (x)
Ionic product = Kw = (2x) (x) = 10-14
⇒ 2x2 = 10-14 ⇒ x =
× 10-8
(x + x) (x)
H2O ⇋ H+ + OH-
(x + x) (x)
Ionic product = Kw = (2x) (x) = 10-14
⇒ 2x2 = 10-14 ⇒ x =
× 10-8 Create a free account to view solution
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