At 90o C, the hydronium ion concentration in pure water is 10−6 M. If 100 ml of 0.5 M-NaOH solution

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At 90o C, the hydronium ion concentration in pure water is 10−6 M. If 100 ml of 0.5 M-NaOH solution is mixed with 250 ml of 0.2 M-HNO3 solution at 90o C, then pH of the resulting solution will be

Accepted Answer

$n_{OH^{-}}	ext{ taken = }\frac{100 	imes 0.5}{1000} = 0.05$$n_{H^{+}}	ext{ taken = }\frac{250 	imes 0.2}{1000} = 0.05$Hence, resulting solution is neutral PH = –log(10–6) = 6.0

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