Ionic EquilibriumHard
Question
The solubility product of BaCrO4 is 2.4 × 10-10 M2. The maximum concentration of Ba(NO3)2 possible without precipitation in a 6 × 10-4 M K2CrO4 solution is
Options
A.4 × 10-7 M
B.1.2 × 1010 M
C.6 × 10-4 M
D.3 × 10-4 M.
Solution
KSP (Ba CrO4) = 2.4 × 10-10 M2
[CrO4-2] = 6 × 10-4 KSP (BaCrO4) = [Ba+2] [CrO4-2] 2.4 × 10-10
⇒ [Ba+] × 6 × 10-4 = 2.4 × 10-10
[Ba+] = 4 × 10-7 M
[CrO4-2] = 6 × 10-4 KSP (BaCrO4) = [Ba+2] [CrO4-2] 2.4 × 10-10
⇒ [Ba+] × 6 × 10-4 = 2.4 × 10-10
[Ba+] = 4 × 10-7 M
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