Ionic EquilibriumHard
Question
Ksp of AgCl is 1.96 × 10-10. 100 mL of saturated AgCl solution is titrated with 1 × 10-5 M NH4 SCN. Volume of 1 × 10-5 M NH4 SCN required precipitate all Ag+ from saturated AgCl solution as AgSCN is:
Options
A.140 mL
B.260 mL
C.70 mL
D.200 mL
Solution
m.moles of Ag+ in 100 ml of saturated solution of AgCl = 
× 100 = 1.4 × 10-3
Now Ag+ + SCN- AgSCN (s)
m.moles of SCN- = m.moles of Ag+
1 × 10-5 × V = 1.4 × 10-3 ⇒ volume = 140 mL.
× 100 = 1.4 × 10-3 Now Ag+ + SCN- AgSCN (s)
m.moles of SCN- = m.moles of Ag+
1 × 10-5 × V = 1.4 × 10-3 ⇒ volume = 140 mL.
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