Trigonometric EquationHard
Question
In a triangle PQR, P is the largest angle and cos 
Further the incircle of the triangle touches the sides PQ, QR and RP at N, L and M respectively, such that the lengths of PN, QL and RM are consecutive even integers. Then possible length(s) of the side(s) of the triangle is (are)
Further the incircle of the triangle touches the sides PQ, QR and RP at N, L and M respectively, such that the lengths of PN, QL and RM are consecutive even integers. Then possible length(s) of the side(s) of the triangle is (are) Options
A.16
B.18
C.24
D.22
Solution
⇒k2 - 3k - 4 = 0
⇒ k = 4, k = -1 (reject)
side lengths 18,22,20
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
For 0 , the solution(s) of cosec cosec = 4√2 is(are)...xf(sin x)dx is equal to...If cot (α + β ) = 0 then sin(α + 2β) =...In a triangle ABC, angle A is greater than angle B. If the measures of angles A and B satisfy the equation 3sin x - 4sin...If 0 [{x cos(cot-1x) + sin(cot-1x) + sin(cot-1x)}2 - 1]1/2 is equal to...