Trigonometric EquationHard
Question
If 0 < x < 1, then 
[{x cos(cot-1x) + sin(cot-1x) + sin(cot-1x)}2 - 1]1/2 is equal to
[{x cos(cot-1x) + sin(cot-1x) + sin(cot-1x)}2 - 1]1/2 is equal toOptions
A.
B.x
C.
D.
Solution
[(x cos cot-1x + sin cot-1x)2 - 1]1/2=
=
(x2 + 1 - 1)1/2 = xCreate a free account to view solution
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