Trigonometric EquationHard
Question
For 0 < θ <
, the solution(s) of
cosec
cosec
= 4√2 is(are)
, the solution(s) of
cosec
cosec
= 4√2 is(are)Options
A.

B.

C.

D.

Solution
Given solutions


= 4√2
⇒ √2 [cot θ - cot (θ + π / 4) + cot (θ + π / 4) - cot (θ + π / 2) + ...+ cot (θ + 5π / 4) - cot (θ + 3π / 2)] = 4√2
⇒ tan θ + cot θ = 4 ⇒ tan θ = 2 ± √3
⇒ θ =


= 4√2⇒ √2 [cot θ - cot (θ + π / 4) + cot (θ + π / 4) - cot (θ + π / 2) + ...+ cot (θ + 5π / 4) - cot (θ + 3π / 2)] = 4√2
⇒ tan θ + cot θ = 4 ⇒ tan θ = 2 ± √3
⇒ θ =

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