Trigonometric EquationHard
Question
For 0 < θ < 
, the solution(s) of 
cosec 
cosec 
= 4√2 is(are)
, the solution(s) of cosec cosec = 4√2 is(are)Options
A.
B.
C.
D.
Solution
Given solutions
= 4√2
⇒ √2 [cot θ - cot (θ + π / 4) + cot (θ + π / 4) - cot (θ + π / 2) + ...+ cot (θ + 5π / 4) - cot (θ + 3π / 2)] = 4√2
⇒ tan θ + cot θ = 4 ⇒ tan θ = 2 ± √3
⇒ θ =
= 4√2⇒ √2 [cot θ - cot (θ + π / 4) + cot (θ + π / 4) - cot (θ + π / 2) + ...+ cot (θ + 5π / 4) - cot (θ + 3π / 2)] = 4√2
⇒ tan θ + cot θ = 4 ⇒ tan θ = 2 ± √3
⇒ θ =
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
The number of intrgral values of k for which the equation 7cos x +5sin x = 2k +1 has asolution, is...=...If tan α = (1 + 2-x)-1, tan β = (1 + 2x+1)-1, then α + β =...If solution of the equation 3cos2θ - 2√3 sin θ cos θ - 3sin2 θ = 0 are nπ + π/r and ...If (1 + tanθ) (1 + tan φ) = 2, then θ + φ =...