Trigonometric EquationHard
Question
For 0 < θ < 
, the solution(s) of 
cosec 
cosec 
= 4√2 is(are)
, the solution(s) of cosec cosec = 4√2 is(are)Options
A.
B.
C.
D.
Solution
Given solutions
= 4√2
⇒ √2 [cot θ - cot (θ + π / 4) + cot (θ + π / 4) - cot (θ + π / 2) + ...+ cot (θ + 5π / 4) - cot (θ + 3π / 2)] = 4√2
⇒ tan θ + cot θ = 4 ⇒ tan θ = 2 ± √3
⇒ θ =
= 4√2⇒ √2 [cot θ - cot (θ + π / 4) + cot (θ + π / 4) - cot (θ + π / 2) + ...+ cot (θ + 5π / 4) - cot (θ + 3π / 2)] = 4√2
⇒ tan θ + cot θ = 4 ⇒ tan θ = 2 ± √3
⇒ θ =
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