Trigonometric EquationHard
Question
If cot (α + β ) = 0 then sin(α + 2β) =
Options
A.sin
B.cos α
C.sin β
D.cos 2β
Solution
cot (α + β) = 0 or α + β = (2n + 1) 
(n ∈ I)
sin (α + 2β) = sin (2α + 2β - α)
= sin [(2n + 1) π - α]
= sin (2nπ + π - α) = sin (π - α) = sinα
(n ∈ I)sin (α + 2β) = sin (2α + 2β - α)
= sin [(2n + 1) π - α]
= sin (2nπ + π - α) = sin (π - α) = sinα
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