Trigonometric EquationHard
Question
xf(sin x)dx is equal toOptions
A.πf(cos x)dx
f(cos x)dxB.πf(sinx)dx
f(sinx)dxC.
f(sinx)dx
f(sinx)dxD.πf(sinx)dx
f(sinx)dxSolution
I = xf(sin x)dx = (π - x)f(sin x)dx
= πf(sin x)dx I
2I = πf(sin x)dx
I =
f(sin x)dx = π f(sin x)dx
πf(cos x)dx
xf(sin x)dx = (π - x)f(sin x)dx= π
f(sin x)dx I2I = π
f(sin x)dxI =
f(sin x)dx = π f(sin x)dxπ
f(cos x)dxCreate a free account to view solution
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