Trigonometric EquationEasy
Question
xf(sin x)dx is equal toOptions
A.π
f(cos x)dx
f(cos x)dxB.π
f(sinx)dx
f(sinx)dxC.
f(sinx)dx

f(sinx)dxD.π
f(sinx)dx
f(sinx)dxSolution
I =
xf(sin x)dx =
(π - x)f(sin x)dx
= π
f(sin x)dx I
2I = π
f(sin x)dx
I =
f(sin x)dx = π
f(sin x)dx
π
f(cos x)dx
xf(sin x)dx =
(π - x)f(sin x)dx= π
f(sin x)dx I2I = π
f(sin x)dxI =

f(sin x)dx = π
f(sin x)dxπ
f(cos x)dxCreate a free account to view solution
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