ElectrochemistryHard
Question
Calculate the cell EMF in mV for
Pt | H2 (1atm) | HCl (0.01 M) | AgCl(s) | Ag(s) at 298 K
if ᐃGfo values are at 25oC - 109.56 kJ/mol for AgCl(s) and - 130.79 kJ/mol for (H+ + Cl-) (aq)
Pt | H2 (1atm) | HCl (0.01 M) | AgCl(s) | Ag(s) at 298 K
if ᐃGfo values are at 25oC - 109.56 kJ/mol for AgCl(s) and - 130.79 kJ/mol for (H+ + Cl-) (aq)
Options
A.456 mV
B.654 mV
C.546 mV
D.None of these
Solution
ᐃGocell reaction = 2 (-130.79) - 2 (- 109.56) = - 42.46 kJ/mole
(for H2 + 2AgCl → 2Ag + 2H+ + 2Cl-)
∴ Eocell =
= + 0.220 V
Now Ecell = + 0.220 +
= 0.456 V = 456 mV.
(for H2 + 2AgCl → 2Ag + 2H+ + 2Cl-)
∴ Eocell =
= + 0.220 VNow Ecell = + 0.220 +
= 0.456 V = 456 mV. Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Which statement is correct....During electrolysis of water the volume of O2 Liberated is 2.24 dm3. The volume of hydrogen liberated, under same condit...ᐃG is the available energy (energy produced) during the electrochemical reaction in galvanic cell which can be con...During discharge of a lead storage cell the density of sulphuric acid in the cell :...For a reaction A(s) + 2B+ → A2+ + B(s); KC has been found to be 1012. The EMF of the cell is...