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Question

Given below are the half-cell reactions
Mn2+ + 2e- → Mn ; Eo = - 1.18 V
(Mn3+ + e- → Mn2+) ; Eo = + 1.51 V
The Eo for 3 Mn2+ → Mn + 2Mn3+ will be

Options

A.- 2.69 V; the reaction will not occur
B.- 2.69 V; the reaction will occur
C.- 0.33 V; the reaction will not occur
D.- 0.33 V; the reaction will occur

Solution

(1) Mn2+ + 2e → Mn ; Eo = - 1.18V ;
    ᐃG1o = - 2F (- 1.18) = 2.36 F
(2) Mn3+ + e → Mn2+ ; Eo = + 1.51 V;
    ᐃG2o = - F(1.51) = - 1.51F
(1) - 2 × (2)
3Mn2+ → Mn + 2Mn3+ ;
    ᐃG3o = ᐃG1o - 2ᐃG2o
    = [2.36 - 2(-1.51)] F
    = (2.36 + 3.02) F
    = 5.38 F
But ᐃG3o = - 2FEo 
⇒     5.38F = - 2FEo
⇒     Eo = - 2.69 V
As Eo value is negative reaction is non spontaneous.

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