ElectrochemistryHard
Question
In the given figure the electrolytic cell contains 1 L of an aqueous 1 M Copper (II) sulphate solution. If 0.4 mole of electrons passed through of cell, the concentration of copper ion after passage of the charge will be
Options
A.0.4 M
B.0.8 M
C.1.0 M
D.1.2 M
Solution
Number of moles of Cu2+ discharged from anode = number of moles of Cu2+ deposited at cathode.
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The electrochemical equivalents of two substances are E1 and E2. The current that must pass to deposit the same amount a...Equal volumes of 0.015 M – CH3COOH and 0.015 M – NaOH solutions are mixed together. What would be the molar conductivity...The standard reduction potentials at 298 K for the following half reactions are given against each : Zn2+(aq) + 2e- V...To a beaker containing 0.1 M – HCl, a little pure solid AgCl is added. Both a silver and a hydrogen electrode (PH2 = 1.0...A volume of 100 ml of 0.6 N−CuSO4 solution is electrolysed between two platinum electrodes till the concentration in the...