ElectrochemistryHard
Question
The ionization constant of a weak electrolyte is 25 × 10-6 while the equivalent conductance of its 0.01 M solution is 19.6 S cm2 eq-1. The equivalent conductance of the electrolyte at infinite dilution (in S cm2 eq-1 ) will be
Options
A.250
B.196
C.392
D.384
Solution
Ka = 25 × 10-6 Λeq = 19.6 Scm2 eq-1, C = 0.01
Ka = 0.01 × α2 ⇒ α =
= 5 × 10-2
α = 5 × 10-2 =
⇒ 
= 
= 392 Scm2 eq-1.
Ka = 0.01 × α2 ⇒ α =
= 5 × 10-2α = 5 × 10-2 =
⇒ = = 392 Scm2 eq-1.Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Using the data in the preceding problem, calculate the equilibrium constant of the reaction at 25oC.Zn + Cu++ ⇋ Zn...Two weak acid solutions HA1 and HA2 each with the same concentration and having pKa values 3 and 5 are placed in contact...Using the standard potential values given below, decide which of the statements I, II, III, IV are correct. Choose the r...A galvanic cell is set up from a zinc bar weighing 100 g and 1.0 L of 1.0 M copper sulphate solution. How long would the...A cell Cu | Cu++ || Ag+ | Ag initially contains 2M Ag+ and 2M Cu++ ions in 1L electrolyte. The change in cell potential ...