ElectrochemistryHard
Question
The ionization constant of a weak electrolyte is 25 × 10-6 while the equivalent conductance of its 0.01 M solution is 19.6 S cm2 eq-1. The equivalent conductance of the electrolyte at infinite dilution (in S cm2 eq-1 ) will be
Options
A.250
B.196
C.392
D.384
Solution
Ka = 25 × 10-6 Λeq = 19.6 Scm2 eq-1, C = 0.01
Ka = 0.01 × α2 ⇒ α =
= 5 × 10-2
α = 5 × 10-2 =
⇒ 
= 
= 392 Scm2 eq-1.
Ka = 0.01 × α2 ⇒ α =
= 5 × 10-2α = 5 × 10-2 =
⇒ = = 392 Scm2 eq-1.Create a free account to view solution
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