ElectrochemistryHard
Question
Using the information in the preceding problem, calculate the solubility product of AgI in water at 25oC [Eo(Ag+, Ag) = + 0.799 volt]
Options
A.1.97 × 10-17
B.8.43 × 10-17
C.1.79 × 10-17
D.9.17 × 10-17
Solution
EoAg|AgI|I- = EoAg+|Ag - 
log 
- 0.151 = 0.799 - log
0.0591 log Ksp = - 0.151 -0.799
log Ksp = - 16.074
Ksp = 8.43 × 10-17
log - 0.151 = 0.799 -
log 0.0591 log Ksp = - 0.151 -0.799
log Ksp = - 16.074
Ksp = 8.43 × 10-17
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