ElectrochemistryHard
Question
The solubility product of silver iodide is 8.3 × 10-17 and the standard reduction potential of Ag, Ag+ electrode is + 0.8 volts at 25oC. The standard reduction potential of Ag,Agl/l- electrode from these data is
Options
A.- 0.30 V
B.+ 0.15 V
C.+ 0.10 V
D.- 0.15 V
Solution
EAg/AgI/I- = 0.8 - 
log 
= 0.8 + 0.0591 × log 8.3 × 10-17
= - 0.15 Volt
or
EAg/AgI/I- = EoAg/Ag+ +
. ln 
= - 0.8 -
log ksp
= - 0.8 - 0.0591. log 8.3 × 10-17
= - 0.8 + 0.095 = 0.15 V.
log = 0.8 + 0.0591 × log 8.3 × 10-17
= - 0.15 Volt
or
EAg/AgI/I- = EoAg/Ag+ +
. ln = - 0.8 -
log ksp = - 0.8 - 0.0591. log 8.3 × 10-17
= - 0.8 + 0.095 = 0.15 V.
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
How much the potential of a hydrogen electrode will change when its solution initially at pH = 0 is neutralised to pH = ...In the electrolysis of CuCl2 soluton using Cu electrodes, the weight of Cu increased by 2gram at cathode. At the anode -...Using same quantity of current, which among Na, Mg and Al is deposited more (by mass) during electrolysis of their molte...The oxidation states of sulphide in S8, S2F2, H2S respectively, are...H2O2 can be prepared by successive reactions:2NH4HSO4 → H2 + (NH4)2S2O8(NH4)2S2O8 + 2H2O → 2NH4HSO4 + H2O2The first reac...