ElectrochemistryHard
Question
The solubility product of silver iodide is 8.3 × 10-17 and the standard reduction potential of Ag, Ag+ electrode is + 0.8 volts at 25oC. The standard reduction potential of Ag,Agl/l- electrode from these data is
Options
A.- 0.30 V
B.+ 0.15 V
C.+ 0.10 V
D.- 0.15 V
Solution
EAg/AgI/I- = 0.8 - 
log 
= 0.8 + 0.0591 × log 8.3 × 10-17
= - 0.15 Volt
or
EAg/AgI/I- = EoAg/Ag+ +
. ln 
= - 0.8 -
log ksp
= - 0.8 - 0.0591. log 8.3 × 10-17
= - 0.8 + 0.095 = 0.15 V.
log = 0.8 + 0.0591 × log 8.3 × 10-17
= - 0.15 Volt
or
EAg/AgI/I- = EoAg/Ag+ +
. ln = - 0.8 -
log ksp = - 0.8 - 0.0591. log 8.3 × 10-17
= - 0.8 + 0.095 = 0.15 V.
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