ElectrochemistryHard
Question
The cell Pt (H2) (1 atm) | (pH = ?) || (a = 1) | AgI(s), Ag has emf, E298K = 0. The standard electrode potential for the reaction AgI + e- → Ag + IQ is - 0.151 volt. Calculate the pH value.
Options
A.3.37
B.5.26
C.2.56
D.4.62
Solution
0 = (- 0.151 - 0) - 
log [H+].
0.0591 × log[H+] = - 0.151
pH =
= 2.56
log [H+].0.0591 × log[H+] = - 0.151
pH =
= 2.56 Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Which of the following is not true about e.m.f. of a cell ?...The reduction potential of hydrogen electrode when placed in a buffer solution is found to be - 0.413V. The pH of the bu...A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams of copper can be liberated by the same curren...A phosphoglyceride is always made up of :...A current of 2.0 ampere passed for 5 hours through a molten tin salt deposits 22.2 gm of metal. The oxidation number of ...