ElectrochemistryHard
Question
The cell Pt (H2) (1 atm) | (pH = ?) || (a = 1) | AgI(s), Ag has emf, E298K = 0. The standard electrode potential for the reaction AgI + e- → Ag + IQ is - 0.151 volt. Calculate the pH value.
Options
A.3.37
B.5.26
C.2.56
D.4.62
Solution
0 = (- 0.151 - 0) - 
log [H+].
0.0591 × log[H+] = - 0.151
pH =
= 2.56
log [H+].0.0591 × log[H+] = - 0.151
pH =
= 2.56 Create a free account to view solution
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