Chemical Kinetics and Nuclear ChemistryMedium
Question
Activation energy of any chemical reaction can be calculated if one knows the value of
Options
A.orientation of reactant molecules during collision
B.rate constant at two different temperatures
C.rate constant at standard temperature
D.probability of collision
Solution
Sol. [Key Concept: Activation energy from two rate constants]
To calculate value of $E_{a}$
Equation used is
$$log\left( \frac{k_{2}}{k_{1}} \right) = \frac{E_{a}}{2.303R}\left( \frac{1}{T_{1}} - \frac{1}{T_{2}} \right)$$
Hence $E_{a}$ can be calculated if value of rate constant $k$ is known at two different temperatures $T_{1}$ and $T_{2}$.
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