Chemical Kinetics and Nuclear ChemistryHard
Question
For the reversible reaction A$\rightleftharpoons$B, the time at which the rate of change in concentration of ‘A’ is equal to the rate of change in concentration of ‘B’ is/are
Options
A.t = 0
B.t = t1/2
C.t = tequilibrium
D.t = infinite
Solution
$- \frac{d\lbrack A\rbrack}{dt} = + \frac{d\lbrack B\rbrack}{dt}\text{ always}$
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