Chemical Kinetics and Nuclear ChemistryHard

Question

For the reversible reaction A$\rightleftharpoons$B, the time at which the rate of change in concentration of ‘A’ is equal to the rate of change in concentration of ‘B’ is/are

Options

A.t = 0
B.t = t1/2
C.t = tequilibrium
D.t = infinite

Solution

$- \frac{d\lbrack A\rbrack}{dt} = + \frac{d\lbrack B\rbrack}{dt}\text{ always}$

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