Basic Maths and Units and DimensionsMedium

Question

A force defined by $F = \alpha t^{2} + \beta t$ acts on a particle at a given time $t$. The factor which is dimensionless, if $\alpha$ and $\beta$ are constants, is:

Options

A.$\alpha\beta t$
B.$\alpha\beta/t$
C.$\beta t/\alpha$
D.$\alpha t/\beta$

Solution

Sol. [Key Concept: Impulse = ∫F dt for a time-varying force]

From principle of homogeneity

$$\begin{matrix} & \lbrack F\rbrack = \left\lbrack \alpha t^{2} \right\rbrack = \lbrack\beta t\rbrack \\ & \lbrack\alpha\rbrack = \frac{\lbrack F\rbrack}{\left\lbrack t^{2} \right\rbrack}\text{~}\text{and}\text{~}\lbrack\beta\rbrack = \frac{\lbrack F\rbrack}{\lbrack t\rbrack} \end{matrix}$$

$$\begin{matrix} \therefore & \lbrack\alpha\rbrack\lbrack t\rbrack = \lbrack\beta\rbrack \\ \therefore & \frac{\alpha t}{\beta} = \text{~}\text{dimensionless}\text{~} \end{matrix}$$

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