ElectrostaticsHard

Question

Using mass (M), length (L), them (T) and current (A) as fundamental quantities, the dimension of permittivity is :

Options

A.ML^-2T²A

B.M^-1L^-3T⁴A²

C.MLT^-2A

D.ML²T^-1A²

Solution

[∈₀] = = M^-1L^-3R⁴A²

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