A3kg ball strikes a heavy gird wall with a speed of 10 m/s at an angle of 60o. It gets with the same

Question

A3kg ball strikes a heavy gird wall with a speed of 10 m/s at an angle of 60^o. It gets with the same speed and angle as shown here. If the ball is in contact with wall for 0.20s, what is the average force exerted on the ball by the wall?

Accepted Answer

Change in momentum along the wall = mv cos 60^o - mv cos60^o = 0
Change in momentum perpendicular to the wall
= mv sin 60^o -(- mv sin60^o) = 2 mv sin 60^o
∴ Applied force

= 50 × 3√3
= 150√3 newton

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