Basic Maths and Units and DimensionsHard
Question
A3kg ball strikes a heavy gird wall with a speed of 10 m/s at an angle of 60o. It gets with the same speed and angle as shown here. If the ball is in contact with wall for 0.20s, what is the average force exerted on the ball by the wall?
Options
A.150 N
B.zero
C.150
D.300N
Solution
Change in momentum along the wall = mv cos 60o - mv cos60o = 0
Change in momentum perpendicular to the wall
= mv sin 60o -(- mv sin60o) = 2 mv sin 60o
∴ Applied force
= 50 × 3√3
= 150√3 newton
Change in momentum perpendicular to the wall
= mv sin 60o -(- mv sin60o) = 2 mv sin 60o
∴ Applied force
= 50 × 3√3 = 150√3 newton
Create a free account to view solution
View Solution FreeTopic: Basic Maths and Units and Dimensions·Practice all Basic Maths and Units and Dimensions questions
More Basic Maths and Units and Dimensions Questions
An observer can see through a pin-hole the top end of a thin rod of height h, placed as shown in the figure. The beaker ...The ratio of one micron to one nanometre is...If it takes 5 minutes to fill a 15 litre bucket from a water tap of diameter cm then the Reynolds number for the flow is...Two stones are thrown up simultaneously with initial speeds u1 and u2 (u2 > u1). They hit the ground after 6s and 10s...An air column, closed at one end and open at the other, resonates with a tuning fork when the smallestlength of the colu...