In an adiabatic expansion, the temperature of one mole of an ideal monatomic gas $(\gamma = 5/3)$ de

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In an adiabatic expansion, the temperature of one mole of an ideal monatomic gas $(\gamma = 5/3)$ decreases from 60 K to 50 K . The work done by the gas in the process is:

(Take the universal gas constant as $R = 8.3\text{ }J{\text{ }mol}^{- 1}{\text{ }K}^{- 1}$ )

Accepted Answer

Sol. [Key Concept: Adiabatic process — TV^(γ−1)=const, W=nRΔT/(1−γ)] Work done in adiabatic process$$\begin{matrix} & W = \frac{nR\Delta T}{1 - \gamma} \ & \Delta T = - 10K \ & W = \frac{1 	imes 8.3 	imes ( - 10)}{1 - \frac{5}{3}} \ & W = \frac{83 	imes 3}{2} \ & W = 124.5	ext{ }J \end{matrix}$$

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