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Question

The amount of carbon dioxide evolved upon complete combustion of 116 g of n-butane is (Given: atomic mass in amu $H = 1,C = 12$ and $O = 16$ )

Options

A.176 g
B.362 g
C.352 g
D.322 g

Solution

Sol. [Key Concept: Combustion stoichiometry — CO₂ from n-butane]

$$\begin{matrix} & C_{4}H_{10} + \frac{13}{2}O_{2} \rightarrow 4{CO}_{2} + 5H_{2}O \\ & \ \because 1\text{~}\text{mole}\text{~}C_{4}H_{10}\text{~}\text{produces}\text{~}4\text{~}\text{mole}\text{~}{CO}_{2} \\ & \ \because 58\text{ }gC_{4}H_{10} \equiv 4 \times 44\text{ }g{CO}_{2} \\ & \ \therefore 116\text{ }gC_{4}H_{10} \equiv \frac{4 \times 44}{58} \times 116 = 352\text{ }g \end{matrix}$$

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