Mole ConceptHard
Question
When 200 g of an oleum sample labelled as 109% is mixed with 300 g of another oleum sample labelled as 118%, the new labelling of resulting oleum sample becomes
Options
A.114.4%
B.112.6%
C.113.5%
D.127%
Solution
200 × 109 + 300 × 118 = 500 × x ⇒ x = 114.4
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
A polystyrene of formula Br3C6H2(C8H8) n was prepared by heating styrene with tribromobenzyl peroxide in the absence of ...The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. The volume of CO2 produced when 100 ml of the...When 500 ml CO2 gas is passed through red hot charcoal, the volume becomes 700 ml. The volume of CO2 converted into CO i...For the complete combustion of 0.2 moles of the sugar, how many moles of oxygen is required ?...The number of F– ions in 4.2 g AlF3 is (Al = 27, F = 19)...