Mole ConceptHard
Question
When 200 g of an oleum sample labelled as 109% is mixed with 300 g of another oleum sample labelled as 118%, the new labelling of resulting oleum sample becomes
Options
A.114.4%
B.112.6%
C.113.5%
D.127%
Solution
200 × 109 + 300 × 118 = 500 × x ⇒ x = 114.4
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
What mass of carbon disulphide CS2 can be completely oxidized to SO2 and CO2 by the oxygen liberated when 325 g of Na2O2...500 c.c of a hydrocarbon (gas) was burnt in excess of oxygen yields 2500 cc of CO2 and 3 litres of H2O vapours (gas), al...A gaseous mixture contains 70% N2 and 30% unknown gas by volume. If the average molecular mass of gaseous mixture is 37....5.85 g of NaCl is dissolved in 1 L of pure water. The number of ions in 1 mL of this solution is...A volume V of a gaseous hydrocarbon was exploded with an excess of oxygen. The observed contraction was 2.5V, and on tre...