Question

Sol. [Key Concept: Kp = Kc(RT)^Δnₐ — relation via change in gas moles]

$$K_{P} = K_{C}(RT)^{\Delta n_{g}}$$

For $K_{P} = K_{C}\left( \Delta n_{g} = 0 \right)$

$$K_{P} \neq K_{C}\left( \Delta n_{g} \neq 0 \right)$$

(1)$H_{2}O(g) + CO(g) \rightleftharpoons H_{2}(\text{ }g) + {CO}_{2}(\text{ }g)$

$$\Delta n_{g} = 0\left( K_{P} = K_{C} \right)$$

(2)$\ N_{2}(\text{ }g) + 3H_{2}(\text{ }g) \rightleftharpoons 2{NH}_{3}(\text{ }g)$

$$\Delta n_{g} = - 2\left( K_{P} \neq K_{C} \right)$$

(3)$\ H_{2}(\text{ }g) + I_{2}(\text{ }g) \rightleftharpoons 2HI(g)$

$$\Delta n_{g} = 0\left( K_{P} = K_{C} \right)$$

(4)$\ N_{2}(\text{ }g) + O_{2}(\text{ }g) \rightleftharpoons 2NO(g)$

$$\Delta n_{g} = 0\left( K_{P} = K_{C} \right)$$