Chemical EquilibriumHard
Question
The equilibrium NH4HS(s) $\rightleftharpoons$NH3(g) + H2S(g) is achieved at the equilibrium pressure of ‘X’ bar at T K. The value of ΔrGo for the reaction is
Options
A.−RT lnX
B.−2RT lnX
C.−2RT (lnX – ln2)
D.−2RT ln(2X)
Solution
NH4HS(s) $\rightleftharpoons$ NH3(g) + H2S(g)
$\frac{X}{2}\text{ bar}$ $\frac{X}{2}\text{ bar}$
$\therefore\Delta G^{o} = - RT.\ln K_{P}^{o} $$$= - RT\ln\left( \frac{X}{2},\frac{X}{2} \right) = - 2RT\left( \ln X - \ln 2 \right)$$
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