Mole ConceptMedium
Question
Complete combustion of X g of an organic compound gave 0.25 g of ${CO}_{2}$ and 0.12 g of $H_{2}O$. If the % of carbon is $25\%$ and of hydrogen is $4.89\%$, then $X =$ $\_\_\_\_$ $\times 10^{- 3}\text{ }g$. (Nearest integer) (Molar mass of $C,H$ and O are 12, 1 and $16\text{ }g{\text{ }mol}^{- 1}$ respectively.)
Options
A.273
B.27
C.2730
D.227
Solution
Sol. [Key Concept: Mass of C $= \frac{12}{44}\ m_{{CO}_{2}}$; then $X = \frac{(mass\ C) \times 100}{\%\ C}$.]
Mass of carbon $= \frac{0.25}{44} \times 12$
Mass% of carbon $= \frac{\text{~}\text{Mass of carbon}\text{~}}{x} \times 100$
$${x = \frac{\frac{0.25 \times 12}{44} \times 100}{25} }{x = \frac{12}{44} }{x = 0.2727 = 272.7 \times 10^{- 3} }{\simeq 273 \times 10^{- 3} }$$
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