Mole ConceptHard
Question
An organic compound contains C, H, and O. If C(%) : H(%) = 6 : 1, what is the simplest formula of the compound, given that one mole of the compound contains half as much oxygen as would be required to burn all the C and H atoms in it to CO2 and H2O ?
Options
A.CH2O
B.C2H4O3
C.C3H6O
D.C3H6O2
Solution
no. of moles= 4.2/420 =0.1
CxH2xOy + 1.5xO2 → xCO2 + xH2O
From the question
= y
x : y = 2 : 3
Formula: C2H4O3.
no. of valence electron in 1 atom = 24
so ans is 0.1*24*NAMolar ratio of C:H = 
= 2:1
Formula of compound, CxH2xOy = 2:1CxH2xOy + 1.5xO2 → xCO2 + xH2O
From the question
= yx : y = 2 : 3
Formula: C2H4O3.
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