AIPMT | 2014Mole ConceptEasy
Question
When 22.4 litres of H2(g) is mixed with 11.2 liters of Cl2 (g), each at STP, the moles of HCl(g) formed is equal to
Options
A.1 mol of HCl(g)
B.2 mol of HCl(g)
C.0.5 mol of HCl(g)
D.1.5 mol of HCl(g)
Solution
H2 + Cl2 → 2HCl
22.4 L 11.2 L Initial
11.2 L 0 22.4 L = 1 mole Final
22.4 L 11.2 L Initial
11.2 L 0 22.4 L = 1 mole Final
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