AIPMT | 2014Mole ConceptHard

Question

When 22.4 litres of H2(g) is mixed with 11.2 liters of Cl2 (g), each at STP, the moles of HCl(g) formed is equal to

Options

A.1 mol of HCl(g)
B.2 mol of HCl(g)
C.0.5 mol of HCl(g)
D.1.5 mol of HCl(g)

Solution

H2 + Cl2   → 2HCl
22.4 L   11.2   L  Initial
11.2 L   0   22.4 L = 1 mole   Final

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