Coordination CompoundHardBloom L3

Question

Consider the complex ion [Cr (NH3)2(C2O4)2] ¯. What is the

(i) oxidation number of the metal atom.

(ii) coordination number of the metal atom.

(iii) charge on the complex if all ligands were chloride ions?

(i) (ii) (iii)

Options

A.–1 6 –3
B.+3 6 –3
C.+3 6 –1
D.–1 5 –3

Solution

Sol. [Cr (NH3)2(C2O4)2]–

Oxidation state → –4 + x = –1

x = 3

co-ordination number → 2 + 4 = 6

Charge on complex if all ligands were chloride ions = + 3 + (–6)

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