Coordination CompoundHard
Question
The correct statement among the following is :
Options
A.$\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ are diamagnetic and $Ni(CO)_{4}$ is paramagnetic.
B.$Ni(CO)_{4}$ and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ are diamagnetic and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ is paramagnetic.
C.$Ni(CO)_{4}$ and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are diamagnetic and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ is paramagnetic.
D.$Ni(CO)_{4}$ is diamagnetic and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are paramagnetic.
Solution
$\ \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -} \rightarrow 3{\text{ }d}^{8} \rightarrow$ diamagnetic $\rightarrow {dsp}^{2}\left\lbrack Ni(CO)_{4} \right\rbrack \rightarrow 3{\text{ }d}^{10} \rightarrow$ diamagnetic $\rightarrow {sp}^{3}\left\lbrack {NiCl}_{4} \right\rbrack^{2 -} \rightarrow 3{\text{ }d}^{8} \rightarrow e^{2,2}t_{2}^{2,1,1} \rightarrow {sp}^{3} \rightarrow$ paramagnetic.
Create a free account to view solution
View Solution FreeMore Coordination Compound Questions
Which of the following is/are inner orbital complex(es) as well as dimagentic in nature ?...Which of the following statements is correct?...The pair(s) of coordination complex/ion exhibiting the same kind of isomerism is(are) -...A d-block element forms octahedral complex but its magnetic moment remains same either in strong field or in weak field ...A complex anion is formed by Osmium (in some oxidation state) with ligands (in proper number so that coordination number...