Coordination CompoundMedium
Question
The correct statement among the following is :
Options
A.$\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ are diamagnetic and $Ni(CO)_{4}$ is paramagnetic.
B.$Ni(CO)_{4}$ and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ are diamagnetic and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ is paramagnetic.
C.$Ni(CO)_{4}$ and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are diamagnetic and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ is paramagnetic.
D.$Ni(CO)_{4}$ is diamagnetic and $\left\lbrack {NiCl}_{4} \right\rbrack^{2 -}$ and $\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -}$ are paramagnetic.
Solution
$\ \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -} \rightarrow 3{\text{ }d}^{8} \rightarrow$ diamagnetic $\rightarrow {dsp}^{2}\left\lbrack Ni(CO)_{4} \right\rbrack \rightarrow 3{\text{ }d}^{10} \rightarrow$ diamagnetic $\rightarrow {sp}^{3}\left\lbrack {NiCl}_{4} \right\rbrack^{2 -} \rightarrow 3{\text{ }d}^{8} \rightarrow e^{2,2}t_{2}^{2,1,1} \rightarrow {sp}^{3} \rightarrow$ paramagnetic.
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