Mole ConceptMedium
Question
In Carius method 0.2425 g of an organic compounds gave 0.5253 g silver chloride. The percentage of chlorine in the organic compound is
Options
A.$53.58\%$
B.$87.65\%$
C.$37.57\%$
D.$34.79\%$
Solution
Organic compound : 0.2425 gm
AgCl obtained : 0.5253 gm
In Carius method for estimation of halogen amount of AgCl obtained is 0.5253 gm from 0.2425 gm of organic compound.
Hence percentage of Cl .
Percentage of $Cl = \underset{\phantom{143.5\ }}{\overset{\phantom{35.5\ }}{\rightarrow}} \times \frac{0.5253}{0.2425} \times 100$
$$= 53.58\%$$
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