Mole ConceptHard
Question
The density of air is 0.001293 g/cm3 at STP. Identify which of the following statement is correct
Options
A.Vapour density is 14.48
B.Molecular weight is 28.96
C.Vapour density is 0.001293 g/cm3
D.Vapour density and molecular weight cannot be determined.
Solution
(A) and (B) Explanation : M. Wt. = 0.001293 × 22400 = 28.96
M.Wt. = d × volume of 1 mole of gas at STP
V. D =
= 14.48
So (A) and (B) are correct answer.
M.Wt. = d × volume of 1 mole of gas at STP
V. D =
= 14.48 So (A) and (B) are correct answer.
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