A solution containing Cu2+ and C2O42- ions which is titrated with 20 ml of M/4 KMnO4 solution in aci

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A solution containing Cu2+ and C2O42- ions which is titrated with 20 ml of M/4 KMnO4 solution in acidic medium completely. The resulting solution is treated with excess of KI after neutralisation. The evolved I2 is then absorbs in 25 ml of N/10 hypo solution, the difference in milli moles of Cu2+ and C2O42- ions in solution is -

Accepted Answer

KMnO4 only oxidises C2O42- ion not Cu2+ So meq. of C2O4 2â€“ = meq. of KMnO4 meq of C2O42-=5Ã—14Ã—20 milli moles ofC2O42-=12.5 meq. of Cu2+ = meq. of hypo {Cu2+â†’ Cu+} wM/1=25Ã—110 milli moles of Cu2+ = 2.5 difference of milli moles = 10

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