Mole ConceptHard

Question

A solution containing Cu2+ and C2O42- ions which is titrated with 20 ml of M/4 KMnO4 solution in acidic medium completely. The resulting solution is treated with excess of KI after neutralisation. The evolved I2 is then absorbs in 25 ml of N/10 hypo solution, the difference in milli moles of Cu2+ and C2O42- ions in  solution is -

Options

A.

10

B.

30

C.

40

D.

50

Solution

KMnO4 only oxidises C2O42- ion not Cu2+
So meq. of C2O4
2– = meq. of KMnO4
meq of C2O42-=5×14×20
milli moles ofC2O42-=12.5
meq. of Cu2+ = meq. of hypo {Cu2+→ Cu+}
wM/1=25×110
milli moles of Cu2+ = 2.5
difference of milli moles = 10

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