Light is incident on a metallic plate having work function $110 imes 10^{- 20} ext{ }J$. If the p

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Light is incident on a metallic plate having work function $110 \times 10^{- 20}\text{ }J$. If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident light is

$\_\_\_\_$ $rad/s.\left( h = 6.63 \times 10^{- 34}\text{ }J.s \right)$

Accepted Answer

$\phi = hv$$$\begin{matrix} & v = \frac{\phi}{h} \ & \omega = 2\pi
u = \frac{2\pi\phi}{h} = \frac{2 	imes 3.14 	imes 110 	imes 10^{- 2}}{6.63 	imes 10^{- 34}} \ & \omega = 1.04 	imes 10^{16}rad/sec \end{matrix}$$

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