Photoelectric EffectHard

Question

Light is incident on a metallic plate having work function $110 \times 10^{- 20}\text{ }J$. If the produced photoelectrons have zero kinetic energy then the angular frequency of the incident light is

$\_\_\_\_$ $rad/s.\left( h = 6.63 \times 10^{- 34}\text{ }J.s \right)$

Options

A.$1.04 \times 10^{16}$
B.$1.04 \times 10^{13}$
C.$1.66 \times 10^{16}$
D.$1.66 \times 10^{15}$

Solution

$\phi = hv$

$$\begin{matrix} & v = \frac{\phi}{h} \\ & \omega = 2\pi\nu = \frac{2\pi\phi}{h} = \frac{2 \times 3.14 \times 110 \times 10^{- 2}}{6.63 \times 10^{- 34}} \\ & \omega = 1.04 \times 10^{16}rad/sec \end{matrix}$$

Create a free account to view solution

View Solution Free
Topic: Photoelectric Effect·Practice all Photoelectric Effect questions

More Photoelectric Effect Questions

The wavelength λ of de Broglie waves associated with an electron (mass m, charge e) accelerated through a potential...The graph of ln (R/R0) versus ln A (R = radius of a nucleus and A = its mass number) is...The structure of solids is studied by :-...If an orbital electron of the hydrogen atom jumps from the ground state to a higher energy state, its orbital speed redu...The de Broglie wavelength of an electron moving with a velocity 1.5 × 108 ms-1 is equal to that of a photon. The ra...