Photoelectric EffectHard

Question

The wavelength λ of de Broglie waves associated with an electron (mass m, charge e) accelerated through a potential difference of V is given by (h is Planck′s constant) :

Options

A.λ = h/mV
B.λ = h/2 meV   
C.λ = h/
D.λ = h/

Solution

λ =

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